python3脚本批量重命名歌曲文件
场景:歌曲文件名有些混乱
于是想用个脚本批量重命名这些歌曲文件,可以选择【歌曲名 - 歌手】或【歌手 - 歌曲名】规范这些文件名
脚本如下:
import os
import re
from mutagen.id3 import ID3, TIT2, TPE1
from mutagen.mp4 import MP4
# 替换后歌手分隔符
REPLACEMENT_STRING = '_'
# 需要被替换掉分隔符
CHARACTERS_TO_REPLACE = ['&', ',', ',',' /', '/']
def replace_characters_in_string(s):
# 替换字符串中的指定字符
for char in CHARACTERS_TO_REPLACE:
s = s.replace(char, REPLACEMENT_STRING)
return s
def get_title_and_artist(filepath):
"""获取歌曲标题和艺术家"""
if filepath.lower().endswith('.mp3'):
audio = ID3(filepath)
title = audio.get('TIT2', None)
artist = audio.get('TPE1', None)
if title and artist:
return title.text[0], artist.text[0]
elif filepath.lower().endswith('.m4a'):
audio = MP4(filepath)
title = audio.get('\xa9nam', None)
artist = audio.get('\xa9ART', None)
if title and artist:
return title[0], artist[0]
return None, None
def rename_file(filepath, format_choice):
"""重命名文件"""
title, artist = get_title_and_artist(filepath)
if title and artist:
# 替换掉歌手中非法字符
artist = replace_characters_in_string(artist)
# 根据格式选择构建新的文件名
if format_choice == '1':
new_name = f"{title} - {artist}"
elif format_choice == '2':
new_name = f"{artist} - {title}"
else:
print("Invalid format choice. Please choose 1 or 2.")
return
# 生成新的文件路径
dir_name = os.path.dirname(filepath)
new_filepath = os.path.join(dir_name, f"{new_name}{os.path.splitext(filepath)[1]}")
# 重命名文件
os.rename(filepath, new_filepath)
print(f'Renamed file: {filepath} -> {new_filepath}')
else:
print(f'Failed to get title or artist for file: {filepath}')
def process_directory(directory, format_choice):
"""遍历目录并重命名文件"""
for root, dirs, files in os.walk(directory):
for file in files:
filepath = os.path.join(root, file)
if file.lower().endswith(('.mp3', '.m4a')):
rename_file(filepath, format_choice)
if __name__ == "__main__":
directory = input("Enter the directory path to process: ")
format_choice = input("Choose the renaming format:\n1. Song Title - Artist\n2. Artist - Song Title\nEnter 1 or 2: ")
process_directory(directory, format_choice)
效果如下:
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